In the given figure each plate of capacitance $C$ has partial value of charge
Medium
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(c) In steady state current drawn from the battery $i = \frac{E}{{({R_2} + r)}}$
In steady state capacitor is fully charged hence No current will flow through line $(2)$
Hence potential difference across line $(1)$ is $V = \frac{E}{{({R_2} + r)}} \times {R_2}$, the same potential difference appears across the capacitor, so charge on capacitor $Q = C \times \frac{{E{R_2}}}{{({R_2} + r)}}$
In steady state capacitor is fully charged hence No current will flow through line $(2)$
Hence potential difference across line $(1)$ is $V = \frac{E}{{({R_2} + r)}} \times {R_2}$, the same potential difference appears across the capacitor, so charge on capacitor $Q = C \times \frac{{E{R_2}}}{{({R_2} + r)}}$
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