Incandescent bulbs are designed by keeping in mind that the resistance of their filament increases with the increase in temperature. If at room temperature, $100 \mathrm{~W}, 60 \mathrm{~W}$ and $40 \mathrm{~W}$ bulbs have filament resistances $\mathrm{R}_{100}, \mathrm{R}_{60}$ and $\mathrm{R}_{40}$, respectively, the relation between these resistances is
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Six resistors of $3 \;\Omega$ each are connected along the sides of a hexagon and three resistors of $6\; \Omega$ each are connected along $A C, A D$ and $A E$ as shown in the figure. The equivalent resistance between $A$ and $B$ is equal to
Resistance $n$, each of $r\; ohm$, when connected in parallel give an equivalentresistance of $R\; ohm$. If these resistances were connected in series, the combination would have a resistance in $ohms$, equal to
If you are provided three resistances $2 \,\Omega$, $3 \,\Omega$ and $6 \,\Omega$. How will you connect them so as to obtain the equivalent resistance of $4 \,\Omega$
A meta sample carrying a current along $x-$ axis with density $J$ is subjected to a magnetic field $B$ (along $z-$ axis). The electric field $E$ developed along $y-$ axis is directly proportional to $J$ as well as $B$. The constant of proportionality has $SI\ unit$
In the circuit shown below $E_1\, =4.0\, V$, $R_1\, = 2\,\Omega$, $E_2\, = 6.0\, V$, $R_2\, = 4\,\Omega$ and $R_3\, = 2\,\Omega$. The current $I_1$ is ............... $\mathrm{A}$