Length of a hollow tube is $5\,m$, it’s outer diameter is $10\, cm$ and thickness of it’s wall is $5\, mm$. If resistivity of the material of the tube is $1.7 \times 10^{-8} \,\Omega m$ then resistance of tube will be
Medium
Download our app for free and get started
(a) By using $R = \rho .\frac{l}{A};$ here $A = \pi (r_2^2 - r_1^2)$
Outer radius $r_2 = 5\,cm$
Inner radius $r_1 = 5 -0.5 = 4.5\, cm$
So $R = 1.7 \times {10^{ - 8}} \times \frac{5}{{\pi \{ {{(5 \times {{10}^{ - 2}})}^2} - {{(4.5 \times {{10}^{ - 2}})}^2}\} }}$
$ = 5.6 \times {10^{ - 5}}\,\Omega $
Outer radius $r_2 = 5\,cm$
Inner radius $r_1 = 5 -0.5 = 4.5\, cm$
So $R = 1.7 \times {10^{ - 8}} \times \frac{5}{{\pi \{ {{(5 \times {{10}^{ - 2}})}^2} - {{(4.5 \times {{10}^{ - 2}})}^2}\} }}$
$ = 5.6 \times {10^{ - 5}}\,\Omega $
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1In the circuit shown below, if the potential at point $A$ is taken to be zero, the potential at point $B$ is .............. $V$View Solution
- 2$A$ battery of $\mathrm{emf}$ $E_0 = 12\, V$ is connected across a $4\,m$ long uniform wire having resistance $4\,\Omega /m$. The cells of small $\mathrm{emfs}$ $\varepsilon_1 = 2\,V$ and $\varepsilon_2 = 4\,V$ having internal resistance $2\Omega$ and $6\Omega$ respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point $N$, the distance of point $N$ from the point $A$ is equal toView Solution
- 3The potential difference in open circuit for a cell is $2.2\, volts$. When a $4\, ohm$ resistor is connected between its two electrodes the potential difference becomes $2\, volts$. The internal resistance of the cell will be .............. $ohm$View Solution
- 4The current in the given circuit is ................ $A$View Solution
- 5View SolutionThe mechanism of the heat produced in a conductor when an electric current flows through it, can be explained on the basis of
- 6For which of the following dependence of drift velocity $v$ on electric field $E$ is ohm's law obeyedView Solution
- 7Figure shows three resistor configurations $\mathrm{R} 1, \mathrm{R} 2$ and $\mathrm{R} 3$ connected to $3 \mathrm{~V}$ battery. If the power dissipated by the configuration $\mathrm{R} 1, \mathrm{R} 2$ and $\mathrm{R} 3$ is $\mathrm{P} 1, \mathrm{P} 2$ and $\mathrm{P} 3$, respectively, thenView Solution
Figure:
- 8In a building there are $15$ bulbs of $45\; \mathrm{W}, 15$ bulbs of $100\; \mathrm{W}, 15$ small fans of $10 \;\mathrm{W}$ and $2$ heaters of $1 \;\mathrm{kW}$. The voltage of electric main is $220\; \mathrm{V}$. The minimum fuse capacity (rated value) of the building will be: .......... $A$View Solution
- 9A current of $10\, amp$ is passing through a metallic wire of cross sectional area $4 \times 10^{-6}\, m ^{2}$. If the density of the aluminum conductor is $2.7\, gm / cc$ considering aluminum gives $1$ electrons per atom for conduction find the drift speed of the electrons is ......... $\times 10^{-4} \,m / s$ if molecular weight of aluminum is $27 \,gm$.View Solution
- 10A parallel combination of two resistors, of $1 \,\Omega$ each, is connected in series with a $1.5 \,\Omega$ resistor. The total combination is connected across a $10\, V$ battery. The current flowing in the circuit is .............. $A$View Solution