MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {1 - {x^2}} - \sqrt {1 + {x^2}} }}{{{x^2}}} = . . .$
- A$1$
- ✓$-1$
- C$-2$
- D$0$
$ = \mathop {\lim }\limits_{x \to 0} \,\frac{{(1 - {x^2} - 1 - {x^2})}}{{{x^2}\,(\sqrt {1 - {x^2}} + \sqrt {1 + {x^2})} }}$
$ = \mathop {\lim }\limits_{x \to 0} \,\frac{{ - 2}}{{\,(\sqrt {1 - {x^2}} + \sqrt {1 + {x^2})} }} = \frac{{ - 2}}{{1 + 1}} = - 1$
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