The current in a simple series circuit is $5.0\, amp$. When an additional resistance of $2.0\, ohms$ is inserted, the current drops to $4.0\, amp$. The original resistance of the circuit in $ohms$ was
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(b) $i \propto \frac{1}{R}\, \Rightarrow \,\frac{{{i_1}}}{{{i_2}}} = \frac{{{R_2}}}{{{R_1}}}$ $ \Rightarrow $ $\frac{5}{4} = \frac{{(R + 2)}}{R}$ $ \Rightarrow $ $R = 8 \,\Omega$
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