Question
The feasible solution for a LPP is shown in given figure. Let Z = 3x-4y be the objective function.
Find the minimum value of Z.

Find the minimum value of Z.


| Corner points | Corresponding value of Z = 3x-4y |
| (0, 0) | 0 |
| (0, 0) | $15 \leftarrow$ Maximum |
| (6, 5) | -2 |
| (6,8) | -14 |
| (4, 10) | -28 |
| (0, 8) | $-32 \leftarrow$ Minimum |
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