The maximum power delivered to resistance $R$ is ............... $W$
Medium
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$P_{\max }=\frac{V_{a b}^{2}}{4 R_{a b}} ; P_{\max }=\frac{16}{4 \times 10}=0.4 \mathrm{\,watt}$
$\mathrm{V}_{\mathrm{ab}}=\frac{12}{9} \times 3=4 \mathrm{\,volt}$
$\mathrm{R}_{\mathrm{ab}}=8+\frac{6 \times 3}{9}=8+2=10\, \Omega$
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