The period of oscillation of a simple pendulum of constant length at earth surface is $T$. Its period inside a mine is
AGreater than $T$
BLess than $T$
CEqual to $T$
D
Cannot be compared
Easy
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AGreater than $T$
a (a) Inside the mine g decreases
hence from $T = 2\pi \sqrt {\frac{l}{g}} $; $T$ increase
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