The springs shown are identical. When $A = 4kg$, the elongation of spring is $1\, cm$. If $B = 6\,kg$, the elongation produced by it is ..... $ cm$
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b) $F = kx$
==> $mg = kx$
==> $m \propto kx$
Hence $\frac{{{m_1}}}{{{m_2}}} = \frac{{{k_1}}}{{{k_2}}} \times \frac{{{x_1}}}{{{x_2}}}$
==> $\frac{4}{6} = \frac{k}{{k/2}} \times \frac{1}{{{x_2}}}$
$ \Rightarrow {x_2} = 3\,cm$.
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