Two bulbs $X$ and $Y$ having same voltage rating and of power $40\, watt$ and $60\, watt$ respectively are connected in series across a potential difference of $300\, volt$, then
A$X$ will glow brighter
BResistance of $Y$ is greater than $X$
CHeat produced in $Y$ will be greater than $X$
DVoltage drop in $X$ will be greater than $Y$
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A$X$ will glow brighter
a (a) Resistance $ \propto \frac{1}{{{\rm{power}}}}$. Thus, $40\, W$ bulb has a high resistance. Because of which there will be more potential drop across $40\, W$ bulb. Thus $40\, W$ bulb will glow brighter.
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