With a potentiometer null point were obtained at 140, cm and 180, cm with cells of emf 1.1 ,V and one unknown X, volts. Unknown

Q: With a potentiometer null point were obtained at $140\, cm$ and $180\, cm$ with cells of $emf$ $1.1 \,V$ and one unknown $X\, volts$. Unknown $emf$ is .............. $V$

d (d) $E = \frac{V}{l}$; $E $ is constant (volt. gradient). $ \Rightarrow $ $\frac{{{V_1}}}{{{l_1}}} = \frac{{{V_2}}}{{{l_2}}}$ $ \Rightarrow $ $\frac{{1.1}}{{140}} = \frac{V}{{180}}$ $ \Rightarrow $ $V = \frac{{180 \times 1.1}}{{140}} = 1.41\,V$ $V = \frac{{180 \times 1.1}}{{140}} = 1.41\,V$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

With a potentiometer null point were obtained at $140\, cm$ and $180\, cm$ with cells of $emf$ $1.1 \,V$ and one unknown $X\, volts$. Unknown $emf$ is .............. $V$

A$1.1$
B$1.8$
C$2.4$
D$1.41$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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