Questions · Page 2 of 4

M.C.Q [1M]

MCQ 511 Mark
To determine the solubility of a solute in water, a solution must be prepared that is___________.
  • A
    Saturated
  • B
    Unsaturated
  • C
    Concentrated
  • D
    Supersaturated
Answer
  1. Saturated

Explanation:

The maximum number of moles of solute that can be dissolved in a given volume of solution represents the solubility of solution.

A solution with the maximum possible amount of solute is saturated.

Hence a saturated solution must be prepared to determine the solubility of a solute in water,

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MCQ 521 Mark
The boiling point of an azeotropic mixture of water and ethanol is less than that of water and ethanol. The mixture shows:
  • A
    No deviation from Raoult’s Law.
  • B
    Positive deviation from Raoult’s Law.
  • C
    Negative deviation from Raoult’s Law.
  • D
    That the solution is unsaturated.
Answer
  1. Positive deviation from Raoult’s Law.
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MCQ 531 Mark
Value of Henry’s constant KH __________.
  • A
    Increases with increase in temperature.
  • B
    Decreases with increase in temperature.
  • C
    Remains constant.
  • D
    First increases then decreases.
Answer
  1. Increases with increase in temperature.

Explanation:

Value of Henry’s constant increases with increase in temperature.

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MCQ 541 Mark
4L of 0.02M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is __________.
  • A
    0.004
  • B
    0.008
  • C
    0.012
  • D
    0.016
Answer
  1. 0.016

Explanation:

Apply the relation, M1V1 = M2V2

Given, M= 0.02M, V= 4L, M= ?, V= 5L

Therefore, 0.02 × 4L = M× 5L

 M= 0.08/5

=0.016M

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MCQ 551 Mark
The Van't Hoff factor of 0.1M Ba(NO3​)2​ solutions is 2.74. The degree of dissociation will be:
  • A
    91.3%
  • B
    87%
  • C
    100%
  • D
    74%
Answer
  1. 87%
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MCQ 561 Mark
Which of the following have least vapour pressure?
  • A
    0.1M NaCl sol
  • B
    0.1M urea sol
  • C
    0.1M AlCl3​ sol
  • D
    0.1M KCl sol
Answer
  1. 0.1M urea sol
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MCQ 571 Mark
The heat of solution or mixing has a negative side.
  • A
    Heat of solution
  • B
    Heat of dissolution
  • C
    Heat of reaction
  • D
    Heat of mixing
Answer
  1. Heat of dissolution

Explanation:

The heat of solution or mixing has a negative side. Dissolution’s heat.

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MCQ 591 Mark
Maximum amount of a solid solute that can be dissolved in a specified amount of a given liquid solvent does not depend upon _______.
  • A
    Temperature.
  • B
    Nature of solute.
  • C
    Pressure.
  • D
    Nature of solvent.
Answer
  1. Pressure.

Explanation:

Solubility of a solid in liquid does not depend upon pressure since solid and liquids are almost incompressible.

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MCQ 601 Mark
To an aqueous solution of NaI, increasing amounts of solid HgI2​ is added, the vapour pressure of the solution:
  • A
    Decreases to a constant value.
  • B
    Increases to a constant value.
  • C
    Increases first and then decreases.
  • D
    Remains constant because HgI2​ is sparingly soluble in water.
Answer
  1. Increases to a constant value.
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MCQ 611 Mark
Which of the following statements is false?
  • A
    Two different solutions of sucrose of same molality prepared in different solvents will have the same depression in freezing point.
  • B
    The osmotic pressure of a solution is given by the equation $\pi=\text{CRT}$ (where C is the molarity of the solution).
  • C
    Decreasing order of osmotic pressure for 0.01M aqueous solutions of barium chloride, potassium chloride, acetic acid and sucrose is BaCl2 > KCl > CH3COOH > sucrose.
  • D
    According to Raoult's law, the vapour pressure exerted by a volatile component of a solution is directly proportional to its mole fraction in the solution.
Answer
  1. Two different solutions of sucrose of same molality prepared in different solvents will have the same depression in freezing point.

Explanation:

Tf = Kfm Since Kf values depend upon the nature of solvent, the depression in freezing point of the solution would not be the same.

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MCQ 621 Mark
Two beakers of capacity 500mL were taken. One of these beakers, labelled as “A”, was filled with 400mL water whereas the beaker labelled “B” was filled with 400mL of 2M solution of NaCl. At the same temperature both the beakers were placed in closed containers of same material and same capacity as shown in. At a given temperature, which of the following statement is correct about the vapour pressure of pure water and that of NaCl solution.
  • A
    vapour pressure in container (A) is more than that in container (B).
  • B
    vapour pressure in container (A) is less than that in container (B).
  • C
    vapour pressure is equal in both the containers.
  • D
    vapour pressure in container (B) is twice the vapour pressure in container (A).
Answer
  1. vapour pressure in container (A) is more than that in container (B).

Explanation:

Since NaCl is a non-volatile solute, it will reduce vapour pressure of the solution. Hence, vapour pressure of pure water in container A is more than in container B.

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MCQ 631 Mark
The rate of vapourisation of water depends upon:
  • A
    Temperature
  • B
    Surface area of container
  • C
    kinetic energy of liquid molecules
  • D
    All of the above
Answer
  1. All of the above

Explanation:

The rate of vapourization of water depends on the temperature and surface area. 

The kinetic energy of molecules depends on the temperature of the water.

Increasing temperature or surface area increases the rate of evaporation and vice-versa.

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MCQ 641 Mark
The incorrect statement is:
  • A
    Vapour pressure of a liquid always increases by increasing temperature.
  • B
    Vapour pressure only depends on temperature and not on the nature of substance.
  • C
    Vapour pressure does not depend on the quantity of the liquid taken and the surface area of the liquid.
  • D
    Vapour pressure is not a colligative property & is independent of the concentration of the liquid.
Answer
  1. Vapour pressure only depends on temperature and not on the nature of substance.

Explanation:

The vapour pressure depends on the temperature and the nature of substance.

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MCQ 651 Mark
On the basis of information given below mark the correct option.
Information: On adding acetone to methanol some of the hydrogen bonds between methanol molecules break.
  • A
    At specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show positive deviation from Raoult’s law.
  • B
    At specific composition methanol-acetone mixture forms maximum boiling azeotrope and will show positive deviation from Raoult’s law.
  • C
    At specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show negative deviation from Raoult’s law.
  • D
    At specific composition methanol-acetone mixture will form maximum boiling azeotrope and will show negative deviation from Raoult’s law.
Answer
  1. At specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show positive deviation from Raoult’s law.

Explanation:

At specific composition methanol-acetone mixture will show positive deviation from Raoulfs law as it has lesser interactions than methanol- methanol and acetone-acetone interactions. Hence it forms minimum boiling azeotrope.

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MCQ 661 Mark
What is an example of camphor in N2 gas?
  • A
    Solid in gas solution
  • B
    Gas in gas solution
  • C
    Solid in liquid solution
  • D
    Liquid in gas solution
Answer
  1. Solid in gas solution

Explanation:

Solid in gaseous solution is an example of camphor in N2 gas. Gaseous solution refers to a solution in which the solvent is gaseous. Other gaseous solutions include air (O2 + N2), iodine vapors in air, humidity in air, and so on.

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MCQ 671 Mark
18g glucose (C6​H12​O6​) is added to 178.2g of water. The vapour pressure of this aqueous solution at 1000C in torr is:
  • A
    7.60
  • B
    76.00
  • C
    752.40
  • D
    759.00
Answer
  1. 752.40

Explanation:

Molecular mass of water = (2 × 1) + (1 × 16) = 18g

For 178.2g water, $\text{n}_\text{A}=\frac{178.2}{18}=9.9\text{mol}$

Molecular mass of glucose = (6)(12) + (12)(1) + 6(16) = 180g.

For 18g glucose, $\text{n}_\text{B}=\frac{18}{180}=0.1\text{mol}$

$\text{X}_{\text{B}}=\frac{0.1}{(0.1+9.9)}=0.01$

$\text{X}_{\text{A}}=1-0.01=0.99$

For lowering of vapour pressure,

$\text{P}=\text{P}^0_\text{A}\text{x}^{\text{A}}=\text{P}^0_\text{A}(1-\text{X}_\text{B})$

$\text{P}=760(1-0.01)$

$\text{P}=760-7.6$

$\text{P}=752.40\ \text{torr}$

Vapour pressure of water is 752.40 torr.

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MCQ 681 Mark
In which case van't Hoff factor is maximum (assuming no hydrolysis)?
  • A
    KCl, 50% ionised
  • B
    K2​SO4​, 40% ionised
  • C
    FeCl3​, 30% ionised
  • D
    SnCl4​, 20% ionised
Answer
  1. FeCl3​, 30% ionised

Explanation:

Soluten a i = [1 + (n -1)a]

KCl 20.51.5

K2​SO4​ 30.41.8 

FeCl3​ 40.31.9

SnCl4​ 50.21.8

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MCQ 691 Mark
Colligative properties are observed when ___________.
  • A
    A non volatile solid is dissolved in a volatile liquid.
  • B
    A non volatile liquid is dissolved in another volatile liquid.
  • C
    A gas is dissolved in non volatile liquid.
  • D
    A volatile liquid is dissolved in another volatile liquid.
Answer
  1. A non volatile solid is dissolved in a volatile liquid.
  2. A non volatile liquid is dissolved in another volatile liquid.

Explanation:

Colligative properties are observed when a non-volatile solid or liquid are dissolved in a volatile liquid.

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MCQ 701 Mark
Intermolecular forces between two benzene molecules are nearly of same strength as those between two toluene molecules. For a mixture of benzene and toluene, which of the following are not true?
  • A
    $\Delta_{\text{mix}}\text{H}=\text{zero}$
  • B
    $\Delta_{\text{mix}}\text{V}=\text{zero}$
  • C
    These will form minimum boiling azeotrope.
  • D
    These will not form ideal solution.
Answer
  1. These will form minimum boiling azeotrope.
  2. These will not form ideal solution.

Explanation:

In a mixture of benzene and toluene intermolecular forces between benzene and toluene molecules would be nearly of the same strength as those of two benzene molecules and two toluene molecules separately. The solution will, therefore, form an ideal solution & obey Raoult’s law. So, the option (iii) & (iv) is not true.

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MCQ 711 Mark
In isotonic solutions ____________.
  • A
    Solute and solvent both are same.
  • B
    Osmotic pressure is same.
  • C
    Solute and solvent may or may not be same.
  • D
    Solute is always same solvent may be different.
Answer
  1. Osmotic pressure is same.
  2. Solute and solvent may or may not be same.

Explanation:

For isotonic solutions osmotic pressure is same, solute or solvent may not be same.

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MCQ 721 Mark
The ratio of the actual value of a colligative property to the value calculated, assuming the substance to be a nonelectrolyte, is referred to as ..................
  • A
    Henry's law
  • B
    Vapor pressure lowering
  • C
    The van't Hoff factor
  • D
    Osmotic pressure
Answer
  1. The van't Hoff factor

Explanation:

The van't Hoff factor is the ratio of the actual value of a colligative property to the value calculated. It is assumed that the substance is a nonelectroyte.

It can also be represented as the ratio of actual number of particles to the number of particles for no ionization.

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MCQ 731 Mark
Which one of the following is a primary standard?
  • A
    Oxalic acid
  • B
    Sodium thiosulphate
  • C
    Sodium hydroxide
  • D
    Potassium dichromate
Answer
  1. Potassium dichromate

Explanation:

The primary standard is a compound of  sufficient purity from which standard solutions of known normalities can be prepared by direct weighing of it and diluting to a defined volume of solution.

Potassium Dichromate(K2​Cr2​O7​) is suitable to be used as a primary standard. It cannot be obtained in very pure form. It readily reacts with any traces of organic material or any other reducing substance in wate

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MCQ 741 Mark
Isotonic solutions must have the same ___________.
  • A
    Solute.
  • B
    Density.
  • C
    Elevation in boiling point.
  • D
    Depression in freezing point.
Answer
  1. Elevation in boiling point.
  2. Depression in freezing point.

Explanation:

Two solutions which have the same osmotic pressure at a given temperature are said to be isotonic in nature. The osmotic pressure of a given solution is given by the formula

$\pi=\text{CRT}=\frac{\text{n}}{\text{VRT}}$

Where π is the osmotic pressure of the solution, C is the concentration, the moles of solute per volume of solvent and T is the temperature, with R being universal gas constant. Osmotic pressure is a colligative property, hence for two solutions to be isotonic, the nature of the solute does not matter, i.e. the solute in the two solutions do not have to be the same. Even the density, which does not have a place in the equation of osmotic pressure does not need to be the same. The isotonic solutions at a given temperature need to have the same volume and same molar concentration, hence they will also have the equal elevation in boiling point and depression in freezing point, two other colligative properties.

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MCQ 751 Mark
On dissolving sugar in water at room temperature solution feels cool to touch. Under which of the following cases dissolution of sugar will be most rapid?
  • A
    Sugar crystals in cold water.
  • B
    Sugar crystals in hot water.
  • C
    Powdered sugar in cold water.
  • D
    Powdered sugar in hot water.
Answer
  1. Powdered sugar in hot water.

Explanation:

Since the solution is cool to touch, the dissolution is endothermic. Therefore, high temperature will favour dissolution. Further, powdered sugar has large surface area and is favourable for dissolution.

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MCQ 761 Mark
The following substances were all dissolved in 100 grams of water at 290K to produce saturated solutions.If the solution is heated to 310K, which substance will have a decrease in its solubility:
  • A
    NaCI
  • B
    KI
  • C
    CaCl2
  • D
    HCI
Answer
  1. HCI

Explanation:

The following substances were all dissolved in 100 grams of water at 290K to produce saturated solutions. If the solution is heated to 310K, HCl will have a decrease in its solubility. HCl is a gas. The solubility of a gas in a solution is inversely proportional to the absolute temperature. With increase in the temperature, the solubility of a gas decreases.

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MCQ 771 Mark
A cylinder filled with a movable piston contains liquid water in equilibrium with water vapour at 25oC. Which one of the following operations results in a decrease in the equilibrium vapour pressure?
  • A
    Moving piston downward a short distance
  • B
    Removing a small amount of vapour
  • C
    Removing a small amount of the liquid water
  • D
    Dissolving salt in the water
Answer
  1. Dissolving salt in the water

Explanation:

Vapour pressure is a surface phenomenon, when the surface area is more, vapour pressure will be more. When we add solute, what we do is we decrease the vapour pressure of solvent because same of the salt ions will be present at the solvent surface, thus taking place of same of the solvent particles which were actively participating in maintain, that previous high value of vapour pressure. So, the equilibrium vapour pressure value decreases. Thus, dissolving salt in water results in decreasing of equilibrium vapour pressure.

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MCQ 781 Mark
Consider the and mark the correct option.
  • A
    Water will move from side (A) to side (B) if a pressure lower than osmotic pressure is applied on piston (B).
  • B
    Water will move from side (B) to side (A) if a pressure greater than osmotic pressure is applied on piston (B).
  • C
    Water will move from side (B) to side (A) if a pressure equal to osmotic pressure is applied on piston (B).
  • D
    Water will move from side (A) to side (B) if pressure equal to osmotic pressure is applied on piston (A).

Answer
  1. Water will move from side (B) to side (A) if a pressure greater than osmotic pressure is applied on piston (B).

Explanation:

Water will move from side (B) to side (A) if pressure greater than osmotic pressure is applied on piston (B) due to reverse osmosis.

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MCQ 791 Mark
Which of the following units is useful in relating concentration of solution with its vapour pressure?
  • A
    Mole fraction.
  • B
    Parts per million.
  • C
    Mass percentage.
  • D
    Molality.
Answer
  1. Mole fraction.

Explanation:

It is mole fraction (x) which is useful in relating concentration of solution with its vapour pressure. For example according to Rault's law in a binary solution of two volatile liquids, p1 = x1 p01 where p1 is vapour pressure of component 1, and x1 is its mole fraction in solution, p01 denotes the vapour pressure of pure solvent.

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MCQ 801 Mark
At equilibrium, the rate of dissolution of a solid solute in a volatile liquid solvent is:
  • A
    Less than the rate of crystallisation
  • B
    Greater than the rate of crystallisation
  • C
    Equal to the rate of crytallisation
  • D
    Zero
Answer
  1. Equal to the rate of crytallisation

Explanation:

Crystallization is the process of the formation of solid crystals precipitating from a solution.

In an unsaturated solution, the rate of dissolution of a solute in a volatile liquid solvent is greater than the rate of crystallization. 

In a supersaturated solution, the rate of dissolution of a solute in a volatile liquid solvent is less than the rate of crystallization.

At equilibrium, the rate of dissolution of a solute in a volatile liquid solvent is equal to the rate of crystallization.

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MCQ 811 Mark
Van’t Hoff factor i is given by the expression __________.
  • A
    $\text{i}=\frac{\text{Normal molar mass}}{\text{Abnormal molar mass}}$
  • B
    $\text{i}=\frac{\text{Abnormal molar mass}}{\text{Normal molar mass}}$
  • C
    $\text{i}=\frac{\text{Observed colligative property}}{\text{Calculated colligative property}}$
  • D
    $\text{i}=\frac{\text{Calculated colligative property}}{\text{Observed colligative property}}$
Answer
  1. $\text{i}=\frac{\text{Normal molar mass}}{\text{Abnormal molar mass}}$
  1. $\text{i}=\frac{\text{Observed colligative property}}{\text{Calculated colligative property}}$
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MCQ 821 Mark
1 mole of liquid A and 9 moles of liquid B are mixed to form a solution. If $\text{P}^\circ_\text{B}​=400_\text{mm}$ of Hg and $\text{P}^\circ_\text{B}​=200_\text{mm}$ of Hg at a temperature 'T' and normal boiling point of liquid B is 300K then answer the questions that follow. 
Given data: Kb ​= 2.7K kg mol−1, Molar mass of B = 100
If 'A' is perfectly non-volatile and it dimerises to an extent of 60% then what will be the vapour pressure of the solution.
  • A
    $\text{360}\text{mm}\ \text{of}\ \text{Hg}$
  • B
    $\frac{3600}{9.7}\text{mm}\ \text{of}\ \text{Hg}$
  • C
    $\frac{4000}{9.7}\text{mm}\ \text{of}\ \text{Hg}$
  • D
    $36\text{mm}\ \text{of}\ \text{Hg}$
Answer
  1. $\frac{3600}{9.7}\text{mm}\ \text{of}\ \text{Hg}$
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MCQ 831 Mark
What happens when a solute crystal is added to a supersaturated solution?
  • A
    It becomes a colloidal solution.
  • B
    The solute dissolves in the solution.
  • C
    The solution desaturates.
  • D
    The solute precipitates out of the solution.
Answer
  1. The solute precipitates out of the solution.

Explanation:

Solute particles leave the solution and form a crystalline precipitate when a solute crystal is added to a supersaturated solution. Seeding refers to the addition of the solute crystal.

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MCQ 841 Mark
What makes a solution?
  • A
    Solute and solvent
  • B
    Solute and solute
  • C
    Solvent and solvent
  • D
    None of the above
Answer
  1. Solute and solvent

Explanation:

The solution is made up of two components that is solute and solvent.

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MCQ 851 Mark
A liquid is kept in a closed vessel. If a glass plate (negligible mass) with a small hole is kept on top of the liquid surface, then the vapour pressure of the liquid in the vessel is :
  • A
    More than what would be if the glass plate were removed
  • B
    Same as what would be if the glass plate were removed
  • C
    Less than what would be if the glass plate were removed
  • D
    Cannot be predicted
Answer
  1. Same as what would be if the glass plate were removed

Explanation:

The vapour pressure of the liquid in the vessel is same as what would be if the glass plate were removed. Vapour pressure is characteristic property of a solvent at a temperature.

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MCQ 861 Mark
The Van't Hoff factors i for an electrolyte which undergoes dissociation and association in solvents are respectively:
  • A
    Greater than one and less than one
  • B
    Less than one and greater than one
  • C
    Less than one and less than one
  • D
    Greater than one and greater than one
Answer
  1. Greater than one and less than one

Explanation:

In case of association of solute particles in solution, the observed molecular weight of solute being more than the normal, the value of factor 'i' is less than unity (i.e. i < 1), while for dissociation the value of i is greater than unity (i.e. i > 1), because the observed molecular weight has lesser value than normal molecular weight.

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MCQ 871 Mark
Vapour pressure of a pure liquid X is 2atm at 300K. It is lowered to  atm on dissolving 1 gof Y in 20g of liquid X. If molar mass of X is 200, what is the molar mass of Y?
  • A
    20
  • B
    50
  • C
    100
  • D
    200
Answer
  1. 50
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MCQ 881 Mark
Which of the following solutions does not  show positive deviation? 
  • A
    Acetone and Ethanol
  • B
    Toluene and Benzene
  • C
    Water and Ethanol
  • D
    Water and Methanol
Answer
  1. Toluene and Benzene

Explanation:

Toluene and Benzene are very similar molecules  and hence are ideal solution,  others are solutions showing positive deviation (Theory based. To be memorized.) 

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MCQ 891 Mark
A closed vessel is maintained at a constant temperature. It is first evacuated and then vapour is injected into it continuously. The pressure of the vapour in the vessel is:
  • A
    Increases continuously
  • B
    First increases and then remains constant
  • C
    First increases and then decreases
  • D
    None of the above
Answer
  1. First increases and then remains constant

Explanation:

The molecules of a gas are in a state of random motion. They continuously collide against the walls of the container. Even at ordinary temperature and pressure, the number of molecular collisions with walls is very large. During each collision, certain momentum is transferred to the walls of the container. The pressure exerted by the gas is due to continuous bombardment of gas molecules against the walls of the container. Due to this continuous bombardment, the walls of the container experience a continuous force which is equal to the total momentum imparted to the walls per second. The average force experienced per unit area of the walls of the container determines the pressure exerted by the gas. This should be clear from the fact that although the molecule collisions are random, the pressure remains constant.

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MCQ 901 Mark
A drop each of two non-corrosive and nonirritating liquids A and B at a temperature of 22oC are placed on the skin. Liquid A gives a more cooling sensation than liquid B. Which of the following can be said about the liquids A and B?
  • A
    Liquid A has higher boiling point than that of liquid B
  • B
    Liquid A has higher latent heat of vaporisation than that of liquid B
  • C
    Liquid A has lower latent heat of vaporisation than that of liquid B
  • D
    The boiling points of liquid A and B are equal
Answer
  1. Liquid A has lower latent heat of vaporisation than that of liquid B

Explanation:

Liquid A gives cooling sensation means liquid A is absorbing more heat from the skin, so, liquid A and B can be differentiated as liquid A has lower latent heat of vaporisation than that of liquid B.

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MCQ 911 Mark
Relative lowering of vapour pressure is a colligative property because__________.
  • A
    It depends on the concentration of a non electrolyte solute in solution and does not depend on the nature of the solute molecules.
  • B
    It depends on number of particles of electrolyte solute in solution and does not depend on the nature of the solute particles.
  • C
    It depends on the concentration of a non electrolyte solute in solution as well as on the nature of the solute molecules.
  • D
    It depends on the concentration of an electrolyte or non electrolyte solute in solution as well as on the nature of solute molecules.
Answer
  1. It depends on the concentration of a non electrolyte solute in solution and does not depend on the nature of the solute molecules.
  2. It depends on number of particles of electrolyte solute in solution and does not depend on the nature of the solute particles.

Explanation:

Relative lowering of vapour pressure depends on concentration of non-electrolyte solute in solution and number of particles of electrolyte solute. It does not depend on nature of solute in both conditions.

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MCQ 921 Mark
If two liquids A and B form minimum boiling azeotrope at some specific composition then ____________.
  • A
    A–B interactions are stronger than those between A–A or B–B.
  • B
    vapour pressure of solution increases because more number of molecules of liquids A and B can escape from the solution.
  • C
    vapour pressure of solution decreases because less number of molecules of only one of the liquids escape from the solution.
  • D
    A–B interactions are weaker than those between A–A or B–B.
Answer
  1. A–B interactions are weaker than those between A–A or B–B.

Explanation:

  1. The solutions which show large positive deviation from Rault's law form minimum boiling azeotrope at some specific composition.
  2. In case of positive deviation from Rault's law A-B interactions are weaker than those between A–A or B–B.
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MCQ 931 Mark
We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentrations 0.1M, 0.01M and 0.001M, respectively. The value of van’t Hoff factor for these solutions will be in the order ____________.
  • A
    iA < iB < iC
  • B
    iA > iB > iC
  • C
    iA = iB = iC
  • D
    iA < iB > iC
Answer
  1. iA = iB = iC

Explanation:

The value of van’t Hoff’s factor will be iA= i= iC due to complete dissociation of strong electrolyte (NaCl) in dilute solutions. On complete dissociation value of i for NaCl is 2.

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MCQ 941 Mark
100 mL of liquid A and 25 mL of liquid B are mixed to formal solution of volume 125 mL. Then the solution is___________.
  • A
    ideal
  • B
    non-ideal with positive deviation
  • C
    non-ideal with negative deviation
  • D
    cannot be predicted
Answer
  1. ideal

Explanation:

As change in volume $(\triangle\text{V})$ is zero so the solution is ideal.

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MCQ 951 Mark
A solution of benzene and toluene is an example of ________ solution.
  • A
    Ideal
  • B
    Non ideal
  • C
    Azeotrope
  • D
    None
Answer
  1. Ideal

Explanation:

Due to absence of polarity, benzene and toluene dont have any interaction forces so they dont show any deviation and forms ideal solutions.

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MCQ 961 Mark
KH value for Ar(g), CO2(g), HCHO(g) and CH4(g) are 40.39, 1.67, 1.83 × 10-5 and 0.413 respectively. Arrange these gases in the order of their increasing solubility.
  • A
    HCHO < CH4 < CO2 < Ar
  • B
    HCHO < CO2 < CH4 < Ar
  • C
    Ar < CO2 < CH4 < HCHO
  • D
    Ar < CH4 < CO2 < HCHO
Answer
  1. Ar < CO2 < CH4 < HCHO

Explanation:

Ar < CO< CH< HCHO Explanation: Higher the value of KH lower will be the solubility of the gas at a given pressure, hence the solubility of given gases would increase with increase in KH values.

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MCQ 971 Mark
The vapour pressures of two liquids A and B in their pure states are in the ratio of 1 : 2. A binary solution of A and B contains A and B in the mole proportion of 1 : 2. The mole fraction of A in the vapour phase of the solution will be:
  • A
    0.33
  • B
    0.2
  • C
    0.25
  • D
    0.52
Answer
  1. 0.2

Explanation:

$\frac{\text{P}^\circ_\text{A}}{\text{P}^\circ_\text{B}}=\frac{1}{2}$

$\frac{\text{X}_{\text{A}}}{\text{X}_{\text{B}}}=\frac{1}{2}$

$\text{P}_{\text{T}}\gamma_\text{A}=\text{P}^\circ_\text{A}\text{x}_\text{A}$

$\therefore\frac{\gamma_\text{A}}{\gamma_\text{B}}=\frac{\text{P}^\circ_\text{A}}{\text{P}^\circ_\text{B}}\frac{\text{X}_\text{A}}{\text{X}_\text{B}}$

We know $\gamma_\text{A}+\gamma_{\text{B}}=1$

$\therefore\gamma_\text{A}=0.2$

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MCQ 981 Mark
At same temperature which pair of the following solutions are isotonic?
  • A
    0.2M BaCl2​ and 0.2M urea
  • B
    0.1M urea and 0.1M NaCl
  • C
    0.1M NaCl and 0.1M K2​SO4​
  • D
    0.1M Ba(NO3​)2​ and 0.1M Na2​SO4
Answer
  1. 0.1M Ba(NO3​)2​ and 0.1M Na2​SO4

Explanation:

Isotonic solutions have the same osmotic pressure and same molar concentration.

The solution of 0.1M Ba(NO3​)2​ and 0.1M Na2​SO4​ are isotonic.

The osmotic pressure of 0.1M Ba(NO3​)2

= iMRT = 3 × 0.1RT = 0.3RT

Osmotic pressure of 0.1M Na2​SO4​

= iMRT = 3 × 0.1RT = 0.3RT

The correct answer is "The solution of 0.1M Ba(NO3​)2​ and 0.1M Na2​SO4​ are isotonic".

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MCQ 991 Mark
Which of the following conditions is not correct for ideal solution:
  • A
    No change in volume on mixing
  • B
    No change in enthalpy on mixing
  • C
    It obeys Raoults law
  • D
    Lonisation of solute should occurs to a small extent
Answer
  1. Lonisation of solute should occurs to a small extent

Explanation:

In an ideal solution, no change in volume on mixing, no change in enthalpy on mixing and it obeys Raoults law but ionisation of solute should not occur to a small extent.

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MCQ 1001 Mark
Which one of the following electrolytes has the same value of van't Hoff's factor (i) as that of Al2​(SO4​)3​ (if all are 100% ionised)?
  • A
    Al(NO3​)3​
  • B
    K4​[Fe(CN)6​]
  • C
    K2​SO4​
  • D
    K3​[Fe(CN)6​]
Answer
  1. K4​[Fe(CN)6​]

Explanatin:

Van't Hoff factor i = $\frac{\text{number of solute particles present in solution}}{\text{theoretical number of solute particles due to solution of non electrolyte }}$

$=\frac{\text{n(observed)}}{\text{n(theoretical)}}.$

1 molecule of Al2​(SO4​)3​ ionizes in solution to produce 5 ions.

$\text{Al}_2(\text{SO}_4)_3\rightarrow2\text{Al}^{3+}+3\text{SO}^2_4$

Hence, i $=\frac{\text{n(observed)}}{\text{n(theoretical)}}=\frac{5}{1}=5.$

1 molecule of K4​[Fe(CN)6​] ionize in solution to produce 5 ions.

K4​[Fe(CN)6​] → 4K++[Fe(CN)6​]4−

Hence, i $=\frac{\text{n(observed)}}{\text{n(theoretical)}}=\frac{5}{1}=5.$

Thus, K4​[Fe(CN)6​] has the same value of van't Hoff's factor (i) as that of Al2​(SO4​)3​ (assuming 100% ionization).

Note: 1 molecule each of Al(NO3​)3​, K2​SO4​ and K3​[Fe(CN)6​] ionizes in solution to produce 4, 3 and 4 ions respectively.

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