MCQ
$1 \,g=$ …… $a.m.u.$
- A$6.02 × 10^{-23}$
- ✓$6.02 × 10^{23}$
- C$1.66 × 10^{-24}$
- D$1.66 × 10^{-27}$
$\therefore \,\,\,1\,\,amu\, = \,1.66 \times \,{10^{ - 24}}\,g\,\,\,(\because \,\,\,1\,kg\, = \,{10^3}\,g)$
$\therefore \,1\,\,g\,\, = \,\frac{1}{{1.66 \times {{10}^{ - 24}}\,\,}}\,\,amu$
$\therefore \,1\,\,g\,\, = \,6.02\, \times \,{10^{23}}\,\,amu$
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