MCQ
A ring of mass $M$ and radius $R$ is rotating about its axis with angular velocity $\omega $. Two identical bodies each of mass $m$ are now gently attached at the two ends of a diameter of the ring. Because of this, the kinetic energy loss will be
- A$\frac{{m\left( {M + 2m} \right)}}{M}\,{\omega ^2}{R^2}$
- B$\frac{{Mm}}{{\left( {M + m} \right)}}\,{\omega ^2}{R^2}$
- ✓$\frac{{Mm}}{{\left( {M + 2m} \right)}}\,{\omega ^2}{R^2}$
- D$\frac{{\left( {M + m} \right)M}}{{\left( {M + 2m} \right)}}\,{\omega ^2}{R^2}$
