A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is $4 \mathrm{~m}$, then the time period of small oscillations will be ____ $s$. $\left[\right.$ take $\left.\mathrm{g}=\pi^2 \mathrm{~ms}^{-2}\right]$
JEE MAIN 2024, Diffcult
Download our app for free and get startedPlay store
Acceleration due to gravity $\mathrm{g}^{\prime}=\frac{\mathrm{g}}{4}$

$T=2 \pi \sqrt{\frac{4 \ell}{g}}$

$T=2 \pi \sqrt{\frac{4 \times 4}{g}}$

 $T=2 \pi \frac{4}{\pi}=8 s$

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    Kinetic energy of a particle executing simple harmonic motion in straight line is $pv^2$ and potential energy is $qx^2$, where $v$ is speed at distance $x$ from the mean position. It time period is given by the expression
    View Solution
  • 2
    For a particle showing motion under the force $F=-5(x-2)^2$, the motion is .......
    View Solution
  • 3
    A block with mass $M$ is connected by a massless spring with stiffiess constant $k$ to a rigid wall and moves without friction on a horizontal surface. The block oscillates with small amplitude $A$ about an equilibrium position $x_0$. Consider two cases: ($i$) when the block is at $x_0$; and ($ii$) when the block is at $x=x_0+A$. In both the cases, a perticle with mass $m$ is placed on the mass $M$ ?

    ($A$) The amplitude of oscillation in the first case changes by a factor of $\sqrt{\frac{M}{m+M}}$, whereas in the second case it remains unchanged

    ($B$) The final time period of oscillation in both the cases is same

    ($C$) The total energy decreases in both the cases

    ($D$) The instantaneous speed at $x_0$ of the combined masses decreases in both the cases

    View Solution
  • 4
    Let $T_1$ and $T_2$ be the time periods of two springs $A$ and $B$ when a mass $m$ is suspended from them separately. Now both the springs are connected in parallel  and same mass $m$ is suspended with them. Now let $T$ be the time period in this position. Then
    View Solution
  • 5
    If the length of the simple pendulum is increased by $44\%$, then what is the change in time period of pendulum ..... $\%$
    View Solution
  • 6
    The displacement of a particle executing simple harmonic motion is given by

    $\mathrm{y}=\mathrm{A}_{0}+\mathrm{A} \sin \omega \mathrm{t}+\mathrm{B} \cos \omega \mathrm{t}$

    Then the amplitude of its oscillation is given by

    View Solution
  • 7
    Two masses, both equal to $100\, g$, are suspended at the ends of identical light strings of length $\lambda = 1.0\, m$, attached to the same point on the ceiling (see figure). At time $t = 0$, they are simultaneously released from rest, one at angle $\theta_1 = 1^o$, the other at angle $\theta_2 = 2^o$ from the vertical. The masses will collide
    View Solution
  • 8
    The kinetic energy of a particle executing $S.H.M.$ is $16\, J$ when it is at its mean position. If the mass of the particle is $0.32 \,kg$, then what is the maximum velocity of the particle ..... $m/s$
    View Solution
  • 9
    Consider two identical springs each of spring constant $k$ and negligible mass compared to the mass $M$ as shown. Fig. $1$ shows one of them and Fig. $2$ shows their series combination. The ratios of time period of oscillation of the two $SHM$ is $\frac{ T _{ b }}{ T _{ a }}=\sqrt{ x },$ where value of $x$ is

    (Round off to the Nearest Integer)

    View Solution
  • 10
    The ratio of frequencies of two pendulums are $2 : 3$, then their length are in ratio
    View Solution