Question
$\int_{-2}^2\left(x^3+1\right) d x$
✓
Answer
$\int_{-2}^2\left(x^3+1\right) d x=\int_{-2}^2\left(x^3\right) d x+\int_{-2}^2 1 d x=I_1+I_2$
$=0+[x]_{-2}^2 \quad$ (As $I_1$ is odd function)
$=2+2$
= 4
$=0+[x]_{-2}^2 \quad$ (As $I_1$ is odd function)
$=2+2$
= 4
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