Masses of three wires of copper are in the ratio of $1 : 3 : 5$ and their lengths are in the ratio of $5:3:1.$ The ratio of their electrical resistances are
AIPMT 1988, Medium
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$R \propto \frac{{{l^2}}}{m}$
$ \Rightarrow $${R_1}:{R_2}:{R_3} $$= {\left( {\frac{{{l_1}}}{{{m_1}}}} \right)^2}:{\left( {\frac{{{l_2}}}{{{m_2}}}} \right)^2}:{\left( {\frac{{{l_3}}}{{{m_3}}}} \right)^2}$
$ = 25:3:\frac{1}{5} \Rightarrow 125:15:1$
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