Two bulbs of $(40 \;W, 200\; V)$ and $(100\; W, 200 \;V)$. Then correct relation for their resistance
AIPMT 2000, Medium
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$P = \frac{{{V^2}}}{R}$
$ \Rightarrow {R_{40}} = \frac{{V_1^2}}{{{P_1}}} = \frac{{{{(200)}^2}}}{{40}} = 1000\,\Omega $ and
${R_{100}} = \frac{{V_2^2}}{{{P_2}}} = \frac{{{{(200)}^2}}}{{100}} = 400\,\Omega $
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