MCQ
When $EM$ wave propagates through vacuum then
- A$E-$ field leads $B-$ field
- B$E-$ field lags $B-$ field
- ✓$E-$ field and $B-$ field are in the same phase
- DEnergy is stored only in $E-$ field
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Reason : An ideal voltmeter draws almost no current due to very large resistance, and hence $(V)$ and $(a)$ will read zero.

